Answer:
Step-by-step explanation:
Given that acceleration of an object is

is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0

So solution for distance is

The linear model of this case takes the form:
y = a(x-b) + k
<span>The cost of having a package delivered has a base fee of $9.70
this is "k" >>>>> k=9.7 (fixed amount of fee)
THEN
</span>
<span>Every pound over 5 lbs cost an additional $0.46 per pound
that means: 0.46(x-5)
in other words, if the package weighs foe example 9 pounds, then 9-5=4, it will cost 0.46*4 for these 4 extra pounds
Finally we have the linear form of this: C = 0.46 (W - 5) + 9.7
</span>
Answer:
Slope(m)=3
Y-intercept= 0
y = 3x +0
Proportional
Step-by-step explanation:
m = -6--12/-2--4
m=6/2
m=3
-12 = 3(-4) + b
-12 = -12 + b
0=b
Answer:
Step-by-step explanation:
3x+8
i am pretty sure about that