Answer:
The diver will hit the water at 1.5 seconds
Step-by-step explanation:
Given
![h= -16(t-1.5)(t+1)](https://tex.z-dn.net/?f=h%3D%20-16%28t-1.5%29%28t%2B1%29)
Required (Missing from the question)
When will the diver hit the water?
To do this, we simply solve for t
When the diver hits the water, the height is 0 (at that point)
So, substitute 0 for h in ![h= -16(t-1.5)(t+1)](https://tex.z-dn.net/?f=h%3D%20-16%28t-1.5%29%28t%2B1%29)
![0= -16(t-1.5)(t+1)](https://tex.z-dn.net/?f=0%3D%20-16%28t-1.5%29%28t%2B1%29)
Divide both sides by -16
![\frac{0}{-16} =\frac{-16(t-1.5)(t+1)}{-16}](https://tex.z-dn.net/?f=%5Cfrac%7B0%7D%7B-16%7D%20%3D%5Cfrac%7B-16%28t-1.5%29%28t%2B1%29%7D%7B-16%7D)
![\frac{0}{-16} =(t-1.5)(t+1)](https://tex.z-dn.net/?f=%5Cfrac%7B0%7D%7B-16%7D%20%3D%28t-1.5%29%28t%2B1%29)
![0 =(t-1.5)(t+1)](https://tex.z-dn.net/?f=0%20%3D%28t-1.5%29%28t%2B1%29)
![(t-1.5)(t+1)=0](https://tex.z-dn.net/?f=%28t-1.5%29%28t%2B1%29%3D0)
Split
or ![t + 1 = 0](https://tex.z-dn.net/?f=t%20%2B%201%20%3D%200)
Solve for t
or ![t = -1](https://tex.z-dn.net/?f=t%20%3D%20-1)
But time (t) can not be negative.
So:
![t = 1.5](https://tex.z-dn.net/?f=t%20%3D%201.5)
Hence, the diver will hit the water at 1.5 seconds