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Ad libitum [116K]
3 years ago
6

During a golf drive, the angular velocity of the driver is 20 rad/s just before impact with the golf ball. If the distance from

the club head to the axis of rotation is 2.0 m, what is the linear velocity of the club head?
Physics
1 answer:
Julli [10]3 years ago
8 0

Answer:

Linear velocity of the club head is 40 m/s

Explanation:

To calculate the linear velocity of the club head, we just need to multiply the angular velocity of the driver (Av = 20 rad/s) by the distance from the club head to the axis of rotation (d = 2.0 m)

So, the linear velocity of the club head (Lv) is:

Lv = Av * d = 20 * 2 = 40 m/s

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charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

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3 years ago
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Answer:

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