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Ad libitum [116K]
3 years ago
6

During a golf drive, the angular velocity of the driver is 20 rad/s just before impact with the golf ball. If the distance from

the club head to the axis of rotation is 2.0 m, what is the linear velocity of the club head?
Physics
1 answer:
Julli [10]3 years ago
8 0

Answer:

Linear velocity of the club head is 40 m/s

Explanation:

To calculate the linear velocity of the club head, we just need to multiply the angular velocity of the driver (Av = 20 rad/s) by the distance from the club head to the axis of rotation (d = 2.0 m)

So, the linear velocity of the club head (Lv) is:

Lv = Av * d = 20 * 2 = 40 m/s

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Answer:

One scientific law that provides the foundation for understanding in chemistry is the law of conservation of matter. It states that in any given system that is closed to the transfer of matter (in and out), the amount of matter in the system stays constant.

Explanation:

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2 years ago
The 1811-1812 new madrid earthquakes were different from most california earthquakes because
g100num [7]

Answer:

New Madrid earthquakes are centered in a plate interior, meaning they were intraplate earthquakes.

Explanation:

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3 years ago
You release a block from the top of a long, slippery inclined plane of length l that makes an angle θ with the horizontal. The m
Alecsey [184]

Answer:

UG (x) = m*g*x*sin(Q)

Vx,f (x)= sqrt (2*g*x*sin(Q))

Explanation:

Given:

- The length of the friction less surface L

- The angle Q is made with horizontal

- UG ( x = L ) = 0

- UK ( x = 0) = 0

Find:

derive an expression for the potential energy of the block-Earth system as a function of x.

determine the speed of the block at the bottom of the incline.

Solution:

- We know that the gravitational potential of an object relative to datum is given by:

                                   UG = m*g*y

Where,

m is the mass of the object

g is the gravitational acceleration constant

y is the vertical distance from datum to the current position.

- We will consider a right angle triangle with hypotenuse x and angle Q with the base and y as the height. The relation between each variable can be given according to Pythagoras theorem as follows:

                                      y = x*sin(Q)

- Substitute the above relationship in the expression for UG as follows:

                                      UG = m*g*x*sin(Q)

- To formulate an expression of velocity at the bottom we can use an energy balance or law of conservation of energy on the block:

                                      UG = UK

- Where UK is kinetic energy given by:

                                      UK = 0.5*m*Vx,f^2

Where Vx,f is the final velocity of the object @ x:

                                     m*g*x*sin(Q) = 0.5*m*Vx,f^2

-Simplify and solve for Vx,f:

                                    Vx,f^2 = 2*g*x*sin(Q)

Hence, Velocity is given by:

                                     Vx,f = sqrt (2*g*x*sin(Q))

8 0
2 years ago
What happens to a falling object when the force of air resistance equals the force of gravity?
12345 [234]

Answer:

A falling object will continue to accelerate to higher speeds until they encounter an amount of air resistance that is equal to their weight.

Explanation:

7 0
2 years ago
Read 2 more answers
A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The velocity of the rock
gtnhenbr [62]
F = m  \frac{v^2}{r}

F= 0.58  \frac{4.5^2}{0.5}  = 23.49 N

5 0
2 years ago
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