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Ad libitum [116K]

3 years ago

6

During a golf drive, the angular velocity of the driver is 20 rad/s just before impact with the golf ball. If the distance from

the club head to the axis of rotation is 2.0 m, what is the linear velocity of the club head?

1 answer:

Julli [10]3 years ago

8 0

Answer:

Linear velocity of the club head is 40 m/s

Explanation:

To calculate the linear velocity of the club head, we just need to multiply the angular velocity of the driver (Av = 20 rad/s) by the distance from the club head to the axis of rotation (d = 2.0 m)

So, the linear velocity of the club head (Lv) is:

Lv = Av * d = 20 * 2 = 40 m/s

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A few years ago, the legal speed limit on the Turner Turnpike was changed from 55.0 mi/h to 75.0 mi/h.

lukranit [14]

The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours

<h3>What is time?</h3>

Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)

To get the time that was saved on the 8.6-mile trip, we use the formula below.

Formula:

Ts = (d/v₁)-(d/v₂)................. Equation 1.

Where:

Ts = Time saved on the trip
d = distance covered during the trip
v₁ = Initial legal speed limit
v₂ = final/current legal speed limit.

From the question,

Given:

d = 86.0 mile
v₁ = 55.0 mi/h
v₂ = 75.0 mi/h

Substitute these values into equation 1

Ts = (86/55)-(86/75)
Ts = 1.564-1.147
Ts = 0.42 h.

Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.

Learn more about time here: brainly.com/question/13893070

6 0

2 years ago

______________ controls the flow of electric current.<br> Answer!!! <br> Please

stepladder [879]

Answer:

Explanation:

Its resistor

8 0

3 years ago

A trebuchet was a hurling machine built to attack the walls of a castle under siege. A large stone could be hurled against a wal

Studentka2010 [4]

(a) 18.9 m/s

The motion of the stone consists of two independent motions:

- A horizontal motion at constant speed

- A vertical motion with constant acceleration ( $g=9.8 m/s^2$ ) downward

We can calculate the components of the initial velocity of the stone as it is launched from the ground:

$u_x = v_0 cos \theta = (25.0)(cos 41.0^{\circ})=18.9 m/s\\u_y = v_0 sin \theta = (25.0)(sin 41.0^{\circ})=16.4 m/s$

The horizontal velocity remains constant, while the vertical velocity changes due to the acceleration along the vertical direction.

When the stone reaches the top of its parabolic path, the vertical velocity has became zero (because it is changing direction): so the speed of the stone is simply equal to the horizontal velocity, therefore

$v=18.9 m/s$

(b) 22.2 m/s

We can solve this part by analyzing the vertical motion only first. In fact, the vertical velocity at any height h during the motion is given by

$v_y^2 - u_y^2 = 2ah$ (1)

where

$u_y = 16.4 m/s$ is the initial vertical velocity

$v_y$ is the vertical velocity at height h

$a=g=-9.8 m/s^2$ is the acceleration due to gravity (negative because it is downward)

At the top of the parabolic path, $v_y = 0$ , so we can use the equation to find the maximum height

$h_{max} = \frac{-u_y^2}{2a}=\frac{-(16.4)^2}{2(-9.8)}=13.7 m$

So, at half of the maximum height,

$h = \frac{13.7}{2}=6.9 m$

And so we can use again eq(1) to find the vertical velocity at h = 6.9 m:

$v_y = \sqrt{u_y^2 + 2ah}=\sqrt{(16.4)^2+2(-9.8)(6.9)}=11.6 m/s$

And so, the speed of the stone at half of the maximum height is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{18.9^2+11.6^2}=22.2 m/s$

(c) 17.4% faster

We said that the speed at the top of the trajectory (part a) is

$v_1 = 18.9 m/s$

while the speed at half of the maximum height (part b) is

$v_2 = 22.2 m/s$

So the difference is

$\Delta v = v_2 - v_2 = 22.2 - 18.9 = 3.3 m/s$

And so, in percentage,

$\frac{\Delta v}{v_1} \cdot 100 = \frac{3.3}{18.9}\cdot 100=17.4\%$

So, the stone in part (b) is moving 17.4% faster than in part (a).

4 0

4 years ago

Which material will displace a volume of water

Nat2105 [25]

Its probably a graduated cylinder of something in that nature

3 0

3 years ago

Read 2 more answers

A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck

Yanka [14]

Answer:0.5

Explanation:

Given

Piece of taffy slams in to sticks to another identical piece and stuck into it.

Let m be the mass of taffy and u be the initial velocity of taffy and v be the final velocity of system.

Conserving momentum

$mu=2mv$

$v=\frac{u}{2}$

Initial kinetic energy $=\frac{mu^2}{2}$

Final Kinetic Energy $=\frac{2m(\frac{u}{2})^2}{2}=\frac{mu^2}{4}$

change in kinetic energy $\Delta K.E.=\frac{mu^2}{2}-\frac{mu^2}{4}=\frac{mu^2}{4}$

change in kinetic energy will contribute in heat energy

thus fraction of kinetic energy converted in to heat $=\frac{heat\ energy}{Initial\ kinetic\ Energy} =\frac{\frac{mu^2}{4}}{\frac{mu^2}{2}}=\frac{1}{2}=0.5$

5 0

4 years ago