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Oksanka [162]
3 years ago
11

What is the G.P.E of 675 newtons on 26000 meter mountain

Physics
1 answer:
vagabundo [1.1K]3 years ago
3 0
GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N

<span>GPE=mgh=675(26000)=17.55x10^6J</span>
You might be interested in
2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
OLEGan [10]

Answer:

Relative\ Velocity = 105m/s

Explanation:

Given

V_A = 45m/s

V_B = 60m/s

Required

Determine the speed of B w.r.t A

The question implies that, we determine the relative velocity of B w.r.t A

Because both trains are moving towards one another, the required velocity is a sum\ of\ velocities\ of both trains:

This is shown below:

Relative\ Velocity = V_A + V_B

Relative\ Velocity = 45m/s + 60m/s

Relative\ Velocity = 105m/s

4 0
3 years ago
Which is the wavelength of a wave that travels at a speed of 3.0 × 10^8 m/s and has a frequency of 1.5 × 10^16 Hz?
k0ka [10]

Answer:

2 x 10^-8

Explanation:

the formula of wavelength is

the speed divided by frequency

so you have the speed given = 3.0x10^8m/s

and frequency = 1.5×10^16 Hz

so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz

7 0
2 years ago
Using the information from Paul Hewitt's Conceptual Development Practice Page 25-1 and the image below, answer the following que
MaRussiya [10]

Answer:

A = 2 cm ,   λ = 8 cm

Explanation:

The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,

We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is

          d = 7-5 = 2 cm

          d = 5-3 = 2 cm

          A = 2 cm

The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.

The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value

          Δx = 8-4 = 4 cm

          λ = 2 Δx

          λ = 8 cm

6 0
3 years ago
A block of mass m=1kg sliding along a rough horizontal surface is traveling at a speed v0=2m/s when it strikes a massless spring
topjm [15]

Here we can use the work energy theorem

W_f + W_s = K_f - K_i

here we know that

K_f = 0

as it come to rest finally

K_i = \frac{1}{2}mv_i^2

K_i = \frac{1}{2}\times 1\times 2^2

K_i = 2 J

now work done by friction force will be given as

W_f = - F_f \times d = -\mu mg d

W_f = - \mu(1)(9.8)(0.10) = - 0.98\mu

Work done by spring force is given as

W_s = \frac{1}{2}k(x_i^2 - x_f^2)

W_s = \frac{1}{2}(10)( 0 - 0.10^2)

W_s = -0.05 J

so now plug in all data above

- 0.05 - \mu(0.98) = 0 - 2

\mu = 1.99

so above is the friction coefficient


4 0
3 years ago
1. Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless
Maslowich
Since momentum is a vector quantity, take any direction as positive and other as negative. Answer won't change.

4 0
3 years ago
Read 2 more answers
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