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sweet [91]
3 years ago
6

If a neutral metal comb is held near an object with a negative charge the comb will become charged by?

Physics
1 answer:
solong [7]3 years ago
6 0
The answer is d because it sets of a negative pulls type thing that makes it negative<span />
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a student moves a box across the floor by exerting 23.3 N of force and doing 47.2 J of work on the box. How far does the student
kozerog [31]
Work = Force x Distance
47.2J = 23.3N x d
d = 47.2/23.3
d = 2.0258 m

hope this helps :P
8 0
3 years ago
The force component along the displacement varies with the magnitude of the displacement, as shown in the graph. (a) 0 to 1.0 m,
Lina20 [59]
Work is force*displacement if the force and displacement is parallel. 


a. You can average the force over the distance so W = Fave*d 

<span>b The force part of that multiplication is zero. </span>

<span>c. You can form the average force for the interval from 2 to 3 and find the work for that section and then consider the interval from 3 to 4, find the work and add the 2 work results.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
5 0
3 years ago
why is it important to create pictorial and physical models before trying to solve an equation, solving a physics problem
Romashka [77]
Many fundamental laws of physics and chemistry can be formulated when doing this.
5 0
2 years ago
Read 2 more answers
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

Hence the force between the balls = 3.036×10⁻¹⁰ N

8 0
3 years ago
A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are rel
Over [174]
The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
                               Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.
6 0
3 years ago
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