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NikAS [45]
3 years ago
15

During combustion, a fuel’s electromagnetic energy is converted into thermal energy.

Physics
1 answer:
swat323 years ago
6 0
True I believe..................
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Which most likely has the greatest conductivity?
Rasek [7]
A warm copper wire will have more conductivity
6 0
3 years ago
Read 2 more answers
A piece of plastic has a net charge of +9.9 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60
Leto [7]

Answer:

The number of protons 6.19 more than electron.

Explanation:

Given that,

Charge Q=+9.9\times10^{-6}\ C

We know that,

formula of charge

Q = nc

Where,

Q = total charge

n = number of protons

e = charge of electron

Put the value into the formula

n = \dfrac{Q}{e}

n=\dfrac{9.9\times10^{-6}}{1.6\times10^{-19}}

n=6.1875\times10^{13}\ C

According to statement of question

Divide the answer by 10^{13}

n=\dfrac{6.1875\times10^{13}}{10^{13}}

n=6.19\ C

Hence, The number of protons 6.19 more than electron.

6 0
3 years ago
Find the angle between forces of 41 pounds and 68 pounds given a magnitude of 87 pounds for the resultant force. (Hint: Write fo
dedylja [7]

Answer:

\theta = 76.9 degree

Explanation:

As we know that the resultant of two vectors is given as

R = \sqrt{F_1^2 + F_2^2 + 2F_1 F_2 cos\theta

here we know that

R = 87 Lb

F_1 = 41 Lb

F_2 = 68 Lb

now we have

87 = \sqrt{41^2 + 68^2 + 2(41)(68)cos\theta

87^2 = 6305 + 5576 cos\theta

\theta = cos^{-1}(\frac{1264}{5576})

\theta = 76.9 degree

7 0
2 years ago
1.Convert 340 cm into m *(answer=0.34m)
Nataly [62]

Answer:

<em>1</em><em>.</em><em>for </em><em>the </em><em>first </em><em>one </em><em>100c</em><em>e</em><em>n</em><em>t</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em> </em><em>make </em><em>1</em><em> </em><em>meter </em><em>therefore</em>

<em>100c</em><em>m</em><em>-</em><em>1</em><em>m</em>

<em>3</em><em>4</em><em>0</em><em>c</em><em>m</em><em>-</em><em>x</em>

<em>3</em><em>4</em><em>0</em><em>/</em><em>100</em>

<em>=</em><em>3</em><em>.</em><em>4</em>

<em>the </em><em>answer </em><em>is </em><em>supposed</em><em> to</em><em> be</em><em> </em><em>3</em><em>.</em><em>4</em><em>,</em><em> maybe</em><em> </em><em>there's</em><em> </em><em>a </em><em>mistake</em><em> </em><em>with </em><em>the </em><em>question</em><em> </em><em>or </em><em>the </em><em>answer</em>

<em>2</em><em>.</em><em>t</em><em>h</em><em>e</em><em> </em><em>weight</em><em> </em><em>of </em><em>a </em><em>body </em><em>is </em><em>given </em><em>by </em><em>the </em><em>formula</em>

<em>mass×</em><em>g</em><em>r</em><em>a</em><em>v</em><em>i</em><em>t</em><em>y</em><em>,</em><em>in </em><em>this </em><em>case </em><em>the </em><em>mass </em><em>is </em><em>7</em><em>5</em><em>k</em><em>g</em><em> </em><em>and </em><em>the </em><em>gravity </em><em>is </em><em>9</em><em>.</em><em>8</em>

<em>weight</em><em>=</em><em>7</em><em>5</em><em>×</em><em>9</em><em>.</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>3</em><em>5</em><em>N</em>

<em>3</em><em>.</em><em>f</em><em>o</em><em>r</em><em> </em><em>this </em><em>one </em><em>the </em><em>mass </em><em>of </em><em>a </em><em>body </em><em>is </em><em>given</em><em> by</em><em> the</em><em> formula</em>

<em>mass=</em><em>weight/</em><em>gravity</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>4</em><em>2</em><em>0</em><em>/</em><em>9</em><em>.</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>4</em><em>2</em><em>.</em><em>8</em><em>k</em><em>g</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

4 0
3 years ago
An object with an initial velocity of 10 m/s accelerates at a rate of 3.5 m/s2 for 8 seconds. How far will it have traveled duri
ICE Princess25 [194]

Answer:

Distance, d = 192 meters

Explanation:

We have,

Initial velocity of an object is 10 m/s

Acceleration of the object is 3.5 m/s²

Time, t = 8 s

We need to find the distance travelled by the object during that time. Second equation of motion gives the distance travelled by the object. It is given by :

d=ut+\dfrac{1}{2}at^2

d=10\times 8+\dfrac{1}{2}\times 3.5\times 8^2\\\\d=192\ m

So, the distance travelled by the object is 192 meters.

4 0
3 years ago
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