Answer:
Explanation:
mass of baseball, m = 0.145 kg
initial velocity, u = 12 m/s upward
(a) final velocity, v = u / 2 = 6 m/s
Let the height is h.
Use third equation of motion
v² = u² - 2gh
6 x 6 = 12 x 12 - 2 x 9.8 x h
36 - 144 = - 19.6 x h
h = 5.51 m
(b) initial kinetic energy, K = 0.5 x m x u² = 0.5 x 0.145 x 12 x 12 = 10.44 J
Final kinetic energy, K' = K/2
0.5 x m x v² = 10.44 /2
0.5 x 0.145 x v² = 5.22
v = 8.5 m/s
v² = u² - 2gh
8.5 x 8.5 = 12 x 12 - 2 x 9.8 x h
72.25 - 144 = - 19.6 x h
h = 3.66 m
Answer
Wavelength= 30*20^8/30=10^7m
Explanation:
Velocity = frequency *wavelength
We're frequency=30HZ
Velocity of light= 3*10^8m/s
Wavelength= 30*20^8/30=10^7m
Explanation:
Answer:
y (t) = 0.754 * cos ( 7.96 t - 69.52)
Explanation:
Given:
m = 1.5 kg , k = 95 N / m , v₀ = 6 m / s , d = 0.35 m , t = 0
y (t) = A * cos ( ω * t - φ )
Using the equation that describe the motion
m * v = - k * x ⇒ m * x'' = - k * x
Angular velocity is equal to
ω = √ k / m ⇒ ω = √ 95 N /m / 1.5 kg
ω = 7.96 rad /s
A = v / ω ⇒ A = 6 m /s / 7.96 rad / s
A = 0.754
d = cos * φ ⇒ φ = cos ⁻¹ * 0.35
φ = 69.52
y (t) = A * cos ( ω * t - φ ) ⇒ y (t) = 0.754 * cos ( 7.96 t - 69.52)
Answer:
212 pounds
Explanation:
477 nm / 180 nm/hr * 80 #/hr = 212 #
