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dolphi86 [110]
3 years ago
8

If you were able to keep the electromagnet that you created in your laboratory activity, what would be two possible uses for the

electromagnet?
Physics
2 answers:
Anna [14]3 years ago
7 0
Picking up metals & making power
iris [78.8K]3 years ago
6 0

Answer:

Electric bells or buzzers

To separate iron and iron objects from a mixture

Explanation:

When a current is passed through current carrying coil with magnetic material at the center, magnetic field is produced. Thus, it acts as temporary magnet. It can be demagnetized by stopping the current. The strength of the magnetic field can be increased by increasing the number of loops and amount of current.

At home, the electromagnet can be used as a buzzer or electric bell. The electromagnet can be connected to a iron armature with a clapper. In the presence of magnetic field, the clapper strikes the bell as the iron armature is pulled towards the field.

The electromagnet can also be used to separate iron objects from a mixture, such as iron nails, clips, pins, needles etc.

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All endothermic reactions absorb heat and make the surroundings warm
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Answer:

b: false

Explanation:

It's true that endothermic reactions absorb heat from their surrounding.  But this makes the surroundings cooler, not warmer.

6 0
3 years ago
Wish if these Are not examples of <br> matter?
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At the same moment, one rock is dropped and one is thrown downward with an initial velocity of 29m/s from the top of a building
Inessa [10]

Answer:

The thrown rock strike 2.42 seconds earlier.

Explanation:

This is an uniformly accelerated motion problem, so in order to find the arrival time we will use the following formula:

x=vo*t+\frac{1}{2} a*t^2\\where\\x=distance\\vo=initial velocity\\a=acceleration

So now we have an equation and unkown value.

for the thrown rock

\frac{1}{2}(9.8)*t^2+29*t-300=0

for the dropped rock

\frac{1}{2}(9.8)*t^2+0*t-300=0

solving both equation with the quadratic formula:

\frac{-b\±\sqrt{b^2-4*a*c} }{2*a}

we have:

the thrown rock arrives on t=5.4 sec

the dropped rock arrives on t=7.82 sec

so the thrown rock arrives 2.42 seconds earlier (7.82-5.4=2.42)

6 0
3 years ago
What must be the magnitude of a uniform electric field if it is to have the same energy density as that possessed by a 0.50 T ma
Sindrei [870]

Answer:

E = 1.50 × 10^{8} V/m

Explanation:

given data

B = 0.50 T

solution

we know that energy density by the magnetic field is express as

\mu _b = \frac{B}{2\mu _o}   ...............1

and

energy density due to electric filed is

\mu _e = \frac{\epsilon _o E^2}{2}     ...............2

and here \mu _b = \mu _ e

so that

E = \frac{B}{\sqrt{\mu _o \times \epsilon _o}}      ...................3

put here value and we get

E = \frac{0.50}{\sqrt{4\pi \times 10^{-7} \times 8.852 \times 10^{-12}}}  

E = 3 × 10^{8}  × 0.50

E = 1.50 × 10^{8} V/m

6 0
3 years ago
What is the kinetic energy of a 55 kilogram skier traveling at meters per second
Rasek [7]
How many meters per second was it traveling
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3 years ago
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