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4 years ago

(7^2-5)x2 can someone please help me and do it STEP BY STEP please in the easiest way STEP BY STEP this is algebra 1

Mathematics

1 answer:

tigry1 [53]4 years ago

5 0

Answer:

Step-by-step explanation:

(7² - 5) × 2

(49 - 5) × 2

(42) × 2

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Which equation represents a line that is perpendicular to the line whose equation is -2y=3x+7

notsponge [240]

Answer:

Any line with the slope of 2/3 would be perpendicular.

Step-by-step explanation:

To find this, first solve the equation for y.

-2y = 3x + 7

y = -3/2x - 7/2

Perpendicular lines always have opposite and reciprocal slopes. Therefore, we flip the slope in the original equation (-3/2 becomes -2/3) and then we change the sign (-2/3 becomes 2/3)

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

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3 years ago

Which are the roots of the quadratic function f(q) = q2 – 125?

qwelly [4]

The solutions to q² - 125 = 0 are q = ±√125.
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3 years ago

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Natasha_Volkova [10]

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3 years ago