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Marrrta [24]
3 years ago
10

Complete each congruence statement by naming the corresponding angle or side. NO LINKS!!!​

Mathematics
2 answers:
Oksanka [162]3 years ago
5 0

Answer:

Solution given:

19

<JKL=<KLS

20

FD=GD

jolli1 [7]3 years ago
4 0

9514 1404 393

Answer:

  19) ∠JKL ≅ ∠SLK

  20) FD ≅ GD

Step-by-step explanation:

It works well to identify the locations of the letters in the congruence statement, then use the letters in the same order from the other part of the congruence statement.

19) Letters JKL have the order 312 in the first part of the congruence statement ΔKLJ ≅ ....

The last part of the congruence statement is ... ≅ ΔLKS. The letters in order 312 from that part are SLK, so we want our angle congruence to read ...

  ∠JKL ≅ ∠SLK

__

20) The letters we're given (FD) are in positions 31 of the first part of the triangle congruence statement. The letters in those positions in the second part are GD, so our segment congruence is ...

  FD ≅ GD

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Ginger buys lunch at school every day. She always gets
shepuryov [24]

Answer:

The estimated probability that Ginger will eat a a pizza everyday of the week is;

D. 8/10 = 80%

Step-by-step explanation:

The given parameters are;

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The outcome of 0 and 1 = No pizza available

The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available

Therefore, we have the;

Group number  {}                          Percentage of time pizza available

1                     {}                          80%

2                     {}                          80%

3                     {}                          80%

4                     {}                          80%

5                     {}                          40%

6                     {}                          100%

7                     {}                          80%

8                     {}                          100%

9                     {}                          80%

10                     {}                          80%

Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8

The number of runs of simulation = 10 runs

The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)

∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10

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