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3 years ago

Trigonometry help please

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

Well use the trig function sin to help.

sin(x) = 6/10 = .6

Then use inverse sign to figure out x.

x = sin^-1(.6) = 36.87 degrees.

Because angle B is not actually 90 those 5 degrees will make angle C larger than 36.87 degrees.

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Use the figure below to find the value of x and PQ.

Scilla [17]

Answer:

x=14

PQ=46

Step-by-step explanation:

PT and TQ are equal, so we can set up the equation like this: PT=TQ

23=2x-5

calculate to find x

x=14

PQ is just PT+TQ so 23+23=46

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2 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

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3 years ago

Which one is greater 3/10 or 2/5

Andreyy89

Answer:

2/5

Step-by-step explanation:

2/5=4/10

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djyliett [7]

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