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anygoal [31]
3 years ago
12

Dana wants to make two types of dog treats. She has 10 cups of peanut butter and 12 cups of flour. Her dog bone treat recipe use

s 3 cups of peanut butter and 2 cups of flour to make one tray. A tray of her oatmeal dog treat recipe uses 1 cup of peanut butter and 4 cups of flour. She plans to sell trays of dog treats at the town festival and charge $6 for a tray of dog bone treats and $7 for a tray of oatmeal treats. Dana wants to maximize her income from selling the dog treats. When writing constraints for the problem, what is the most reasonable definition for the variables x and y? Let x represent the number of cups of peanut butter used and y represent the number of cups of flour used. Let x represent the number of cups of peanut butter used and y represent the number of trays of dog bone treats made. Let x represent the number of dog bone treats made and y represent the number of cups of flour used. Let x represent the number of trays of dog bone treats made and y represent number of trays of oatmeal dog treats made.
Mathematics
2 answers:
almond37 [142]3 years ago
6 0

Answer:D

Step-by-step explanation:

strojnjashka [21]3 years ago
4 0
Let x represent the number of trays of dog bone treats made and y represent number of trays of oatmeal dog treats made.
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3x + 2 = 11 what is x?
nevsk [136]

Answer:

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Step-by-step explanation:

3x + 2 = 11

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Answer:

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Answer:

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Step-by-step explanation:

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2 years ago
ten selected students took a. altitude test out of the total score of 100 these students scored 60,50,50,70,40,80,65,55,50 and 9
ira [324]

<u>Answer:</u>

• mean = 61

• mode = 50

• median = 57.5

<u>Step-by-step explanation:</u>

• The mean is calculated by adding all the values together, and dividing the result by the number of values.

∴ mean =  \frac{60 + 50 + 50 + 70 + 40 + 80 + 65 + 55 + 50 + 90}{10}

⇒ mean = \frac{610}{10}

⇒ mean = 61

• The mode of a set of values is the value that is the most common (has highest frequency) among them.

50 is the most common value.

∴ mode = 50

• The median is the middle-value of a set of ordered values.

∴ We have to first rearrange the set:

⇒  40, 50, 50, 50, 55, 60, 65, 70, 80, 90

Now we need to find the middlemost value:

Since we have 10 values, which is an even number, we have to use the formula:

median = \frac{(n/2)^{th} \space\ term  \space\ + \space\ [(n/2) + 1]^{th} \space\ term  }{2}

where n is the number of values.

∴ median =  \frac{(10/2)^{th} \space\ term  \space\ + \space\ [(10/2) + 1]^{th} \space\ term  }{2}

⇒ median =  \frac{5^{th} \space\ term  \space\ + \space\ 6^{th} \space\ term  }{2}

The 5th and 6th terms in our ordered series are 55 and 60 respectively.

∴ median = \frac{55 + 60}{2}

⇒ median = 57.5

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