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anygoal [31]
4 years ago
12

Dana wants to make two types of dog treats. She has 10 cups of peanut butter and 12 cups of flour. Her dog bone treat recipe use

s 3 cups of peanut butter and 2 cups of flour to make one tray. A tray of her oatmeal dog treat recipe uses 1 cup of peanut butter and 4 cups of flour. She plans to sell trays of dog treats at the town festival and charge $6 for a tray of dog bone treats and $7 for a tray of oatmeal treats. Dana wants to maximize her income from selling the dog treats. When writing constraints for the problem, what is the most reasonable definition for the variables x and y? Let x represent the number of cups of peanut butter used and y represent the number of cups of flour used. Let x represent the number of cups of peanut butter used and y represent the number of trays of dog bone treats made. Let x represent the number of dog bone treats made and y represent the number of cups of flour used. Let x represent the number of trays of dog bone treats made and y represent number of trays of oatmeal dog treats made.
Mathematics
2 answers:
almond37 [142]4 years ago
6 0

Answer:D

Step-by-step explanation:

strojnjashka [21]4 years ago
4 0
Let x represent the number of trays of dog bone treats made and y represent number of trays of oatmeal dog treats made.
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its d 5/8

Step-by-step explanation:

use slope equation

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3 years ago
The probability of winning on an arcade game is 0.568. If you play the arcade game 22 times, what is the probability of winning
Serggg [28]

The probability of winning 15 out of the 22 games is P = 0.099

<h3>what is the probability of winning more than 15 times?</h3>

We know that the probability of winning on the arcade game is 0.568.

Then the probability of losing is:

P = 1 - 0.568 = 0.432

The probability of winning 15 out of 22 games is given by the equation:

P = C(22, 15)*(0.568)^{15}*(0.432)^{7}

Where C(22, 15) is the number of combinations of 15 elements that we can make with a set of 22 elements, given by:

C(22, 15) = \frac{22!}{(22 - 15)!*15!}  = \frac{22!}{7!*15!} = \frac{22*21*20*19*18*17*16}{7*6*5*4*3*2*1} = 170,544

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If you want to learn more about probability:

brainly.com/question/25870256

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2 years ago
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liraira [26]

Answer:

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Step-by-step explanation:

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Hopefully this helps!

Brainliest please?

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2 years ago
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