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2 years ago

How do you identify points on a graph i need a small answer and i need it quick lol thx

1 answer:

8 0

You can identify points on a graph by looking at them. The x coordinate is the horizontal line. and the vertical line is the y axis

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mamaluj [8]

Answer:

$291.50

Step-by-step explanation:

For 22 hours, he earns 22 times his hourly pay.

22×$13.25 = $291.50

6 0

3 years ago

mr_godi [17]

She sent 8 letters 12-4=8

3 0

3 years ago

umka21 [38]

1379.52 is the answer to your question

4 0

2 years ago

Likurg_2 [28]

The answer should be $20.77

6 0

3 years ago

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

5 0

3 years ago