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tigry1 [53]
3 years ago
11

If we let the domain be all animals, and S(x) = "x is a spider", I(x) = " x is an insect", D(x) = "x is a dragonfly", L(x) = "x

has six legs", E(x, y ) = "x eats y", then the premises be
"All insects have six legs," (∀x (I(x)→ L(x)))
"Dragonflies are insects," (∀x (D(x)→I(x)))
"Spiders do not have six legs," (∀x (S(x)→¬L(x)))
"Spiders eat dragonflies." (∀x, y (S(x) ∧ D(y)) → E(x, y)))
The conditional statement "∀x, If x is an insect, then x has six legs" is derived from the statement "All insects have six legs" using _____.

a. existential generalization
b. existential instantiation
c. universal instantiation
d. universal generalization
Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

Answer:

The conditional statement "∀x, If x is an insect, then x has six legs" is derived from the statement "All insects have six legs" using "a. existential" generalization

Step-by-step explanation:

In predicate logic, existential generalization is a valid rule of inference that allows one to move from a specific statement, or one instance, to a quantified generalized statement, or existential proposition. In first-order logic, it is often used as a rule for the existential quantifier in formal proofs.

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4 years ago
A square and a regular hexagon have side of the same length. The perimeter of the square increased by 48 units will be equal to
butalik [34]

The length of the side of the hexagon or square is 24 units.

<u>Step-by-step explanation:</u>

It is given that, a square and a regular hexagon have side of the same length.

The length is not given in the problem. So, let us assume the length of the side of hexagon or square as 'x'.

The additional information given is that, the perimeter of the square increased by 48 units will be equal to the perimeter of the hexagon.

  • The perimeter of the square = 4 × length of the side.
  • Then, the perimeter of the square increased by 48 units = (4x + 48).
  • The perimeter of the hexagon = 6 × length of the side.
  • Therefore, the perimeter of the hexagon = 6x.

<u>To calculate the length x of square and hexagon :</u>

Comparing both the perimeters of square and hexagon,

⇒ (4x + 48) = 6x

⇒ 48 = 6x-4x

⇒ 2x = 48

⇒ x = 48/2

⇒ x = 24 units.

The length of the side of the hexagon or square is 24 units.

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