Hello,
2ay²+5ay-3a=a(2y²+5y-3)
=a(2y²+6y-y-3)=a(2y(y+3)-(y+3))
=a(y+3)(2y-1)
0= -3x+9
-9=-3x
3=x
Final answer: x=3
There is only one zero because it is linear, and can therefore only cross the x axis once.
Jason likely missed placed the decimal, because 3 x 1 = 3, and if the decimal was between 2 and 5, the number would be near 3.
Answer:
126
Step-by-step explanation:
word your question a little better next time this was almost illegible.
