If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle? A) x2 +
(y + 2)2 = 36 B) x2 + (y + 2)2 = 52 C) x2 + (y − 2)2 = 36 D) x2 + (y − 2)2 = 52
1 answer:
Answer:
D) x² + (y − 2)² = 52
Step-by-step explanation:
The center of the circle is the midpoint of the diameter, so is the average of the end points:
(h, k) = ((-6, 6) +(6, -2))/2 = (0, 4)/2 = (0, 2)
Then the distance between the center and an end point is the radius. It is found using the distance formula:
r = √((x2 -x1)² +(y2 -y1)²) = √((-6 -0)² +(6 -2)²) = √(36 +16) = √52
Putting these values into the standard form equation for a circle ...
(x -h)² +(y -k)² = r²
gives ...
(x -0)² +(y -2)² = (√52)²
x² +(y -2)² = 52 . . . . . matches choice D
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Hi! Your answer is q = -9
Please see an explanation for a better and clear understanding to your problem.
Any questions about my answer and explanation can be asked through comments! :)
Step-by-step explanation:
Since we want to solve for q-term. That means we are going to isolate q-term.
We can add 4 and 9 together.
Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.
We are reaching to the final step where we divide the whole equation by 3.
Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!
To check the answer, simply substitute q = -9 in the equation.
Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.
Hope this helps!