Answer:
The answer is "Data Cleaning".
Explanation:
In the given question some information is missing, that is the option of the question, which can be described as follows:
A) Data Gathering
B) Data Description
C) Data Cleaning
D) Exploratory Data Analysis
Information cleaning is the method of processing information, that may not be accurate, complete, obsolete, replicated. It is used in to review the deleted and changing information, and certain options choice is incorrect, that can be explained as follows:
- In option A, It is used in collecting data.
- In option B, It provides the details about the data.
- In option D, It is used in the statistical model for analyzing the data.
guess its d drivers , since u said wen it gets outdated
Answer:
1) Grasslands are areas where the vegetation is dominated by grasses. However, sedge and rush can also be found along with variable proportions of legumes, like clover, and other herbs. Grasslands occur naturally on all continents except Antarctica and are found in most ecoregions of the Earth.
2) Animals adapt to the shortage of water and food through various ways, including migrating (moving to another area) and hibernating until the season is over. Grazing animals, like gazelles and zebras, feed on grasses and often use camouflage to protect themselves from predators when they are roaming in the open.
3) Grasslands clearly provide the feed base for grazing livestock and thus numerous high-quality foods, but such livestock also provide products such as fertilizer, transport, traction, fibre and leather.
<h3>Hope it helps u✌️</h3>
Answer:
Check the explanation
Explanation:
Generally, average access time is :
hit rate * ( cache access time ) //since data found in cache
+
miss rate * ( cache access time + time to hit memory to get data from memory) // miss occurred
In this case, parallel access is happening, so we don't need to add cache access time when
a miss occurs. Therefore, in this case the formula becomes:
avg(time) = hit rate * ( cache access time )
+
miss rate * ( time to hit memory to get data from memory)
Given,
hit rate= 0.95
miss rate = 1- hit rate = 1-0.95 = 0.05
cache access time = 15 ns
memory access time = 220 ns
Put values in formula:
avg(time) =0.95 * 15 + 0.05 * 220
=25.25 ns