Answer:
solution below
Step-by-step explanation:
The question says 6 working mother's were selected so <u>n = 6</u><u> </u><u>not</u><u> </u><u>0</u><u>.</u><u>6</u>
We are expected to find
P(X = 0,1,2,3,4,4,6)
1. <u>When x = 0</u>
6C0*(0.34)⁰*(0.66)⁶
= 1 *1* 0.827
= 0.0827
<u>2. When X = 1</u>
6C1*(0.34)¹*(0.66)⁵
= 6 x 0.34 x 0.252
= 0.2555
<u>3. When X = 2</u>
6C2*(0.34)²*(0.66)⁴
= 15 x 0.1156 x 0.1897
= 0.3289
<u>4. When x = 3</u>
6C3*(0.34)³*(0.66)³
20 x 0.039304 x 0.2875
= 0.2599
<u>5. When X = 4</u>
6C4*(0.34)⁴*(0.66)²
= 15 x 0.01336 x 0.4356
= 0.8729
<u>6. When x = 5</u>
6C5*(0.34)⁵*(0.66)¹
= 6 x 0.0045 x 0.66
= 0.01782
<u>7. When x = 6</u>
6C6*(0.34)⁶*(0.66)⁰
1 x 0.0015 x 1
= 0.0015
Answer:
$20.06
Step-by-step explanation:
17 x 0.18 = 3.06 Multiply the cost by the tip percent
17 + 3.06 = $20.06 Add the tip amount to the original cost
a = amount invested at 13%
b = amount invested at 2%
we know the total amount invested is 8200, so if the first amount is say "a", the second amount must be the slack left from subtracting "a", namely b = 8200 - a.
we also know 13% of "a" plus 2% of "b" yielded an interest of $461 in a year.
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{13\% of a}}{\left( \cfrac{13}{100}\right)a\implies 0.13a}~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)b\implies 0.02b} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B13%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B13%7D%7B100%7D%5Cright%29a%5Cimplies%200.13a%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B2%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B2%7D%7B100%7D%20%5Cright%29b%5Cimplies%200.02b%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

It’s 2.03, you just put it into a calculator