The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.
The reactions are given as follows :
1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :
CH₃CH₂COOH + CH₃Li ------> CH₃CH₂COCH₃
2 butanone
2) the reaction of carboxylic acid with SOCl₂ is given as follows :
CH₃CH₂COOH + SOCl₂ -----> CH₃CH₂COCl
3) the reaction of carboxylic acid with CH₃NH₂ is given as follows
CH₃CH₂COOH + CH₃NH₂ -----> CH₃CH₂CONHCH₃
Thus, The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
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Answer:
Choice B. The solid with hydrogen bonding.
Assumption: the molecules in the four choices are of similar sizes.
Explanation:
Molecules in a molecular solid are held intact with intermolecular forces. To melt the solid, it is necessary to overcome these forces. The stronger the intermolecular forces, the more energy will be required to overcome these attractions and melt the solid. That corresponds to a high melting point.
For molecules of similar sizes,
- The strength of hydrogen bonding will be stronger than the strength of dipole-dipole attractions.
- The strength of dipole-dipole attractions (also known as permanent dipole) will be stronger than the strength of the induced dipole attractions (also known as London Dispersion Forces.)
That is:
Strength of Hydrogen bond > Strength of Dipole-dipole attractions > Strength of Induced dipole attractions.
Accordingly,
Melting point due to Hydrogen bond > Melting point due to Dipole-dipole attractions > Melting point due to Induced Dipole attractions.
- Induced dipole is possible between all molecules.
- Dipole-dipole force is possible only between polar molecules.
- Hydrogen bonds are possible only in molecules that contain
atoms that are bonded directly to atoms of
,
, or
.
As a result, induced dipoles are the only force possible between molecules of the solid in choice C. Assume that the molecules are of similar sizes, such that the strengths of induced dipole are similar for these molecules.
Melting point in choice B > Melting point in choice D > Melting point in choice A and C.
Answer:
Explanation:
Li+H2O..................LiOH+H2
mass of Li=17.8 g
No of moles of Li=17.8/7=2.5
mass of H2O=50.0 g
No of moles of H2O=50.0/18=2.8
limiting reagent is Li so 1 mole of Li produce 1 mole of LiOH therefore 2.5 mole of Li produce 2.5 moles of LiOH now we have to convert it into grams
moles=given mass/molar mass
given mass=moles*molar mass
molar mass of LiOH=24
mass=2.5*24=60 gram
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