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Mariulka [41]
2 years ago
11

When an electron moves from a higher energy level to a lower energy level in an atom, Choose one: A. the atom is ionized. BY. a

continuous spectrum is emitted. C. a photon is absorbed. D. a photon is emitted.
Chemistry
1 answer:
Ad libitum [116K]2 years ago
4 0

The movement of an electron from a higher energy level to a lower energy level in an atom, a photon is emitted.

<h3>What is photon?</h3>

Photon can be defined as those particles in a quantum of light. It is also defined as a particle of light.

However, Photons are usually emitted or released when electrons moved from a higher energy level to a lower energy level.

<h3>What is an atom?</h3>

An atom is the smallest particles of an element which can take part in a chemical reaction.

  • Some substances are monoatomic consisting of only one atom

  • Some are diatomic consisting of two atoms, Example: Oxygen atoms ( O2 ), Hydrogen atoms ( H2 )

  • Some atoms such as Ozone ( O3 ) are triatomic consisting of three atoms.

  • Some are polyatomic

Learn more about atoms:

brainly.com/question/14464650

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A student dissolves 10.7 g of lithium chloride (LiCl) in 300. g of water in a well-insulated open cup. He then observes the temp
Novosadov [1.4K]

Answer:

1) Exothermic.

2) Q_{rxn}=-8580J

3) \Delta _rH=-121.0kJ/mol

Explanation:

Hello there!

1) In this case, for these calorimetry problems, we can realize that since the temperature increases the reaction is exothermic because it is releasing heat to solution, that is why the temperature goes from 22.0 °C to 28.6 °C.

2) Now, for the total heat released by the reaction, we first need to assume that all of it is absorbed by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

Q_{rxn}=-m_{Total}C(T_2-T_1)\\\\Q_{rxn}=-(300g+10.7g)*4.184 \frac{J}{g\°C} (28.6\°C-22.0\°C)\\\\Q_{rxn}=-8580J

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case LiCl, we proceed as follows:

\Delta _rH=\frac{Q_{rxn}}{n_{LiCl}} \\\\\Delta _rH=\frac{-8580J}{10.7g*\frac{1mol}{150.91g} }*\frac{1kJ}{1000J}  \\\\\Delta _rH=-121.0kJ/mol

Best regards!

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Answer:

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