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Answer:
The pressure inside the container is 6.7 atm
Explanation:
We have the ideal gas equation: P x V = n x R x T
whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.
So we can calculate the pressure by
P = n x R x T / V
where as,
n = 41.1 g / 44 g/mol = 0.934 mol
Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm
Answer:
I hope this link helps you.
Explanation:
http://astronomy.swin.edu.au/cosmos/P/Phases
Answer:
75
Explanation:
is the answer for your question
Answer:
17.5609g
Explanation:
According to the question, a sample of mass 6.814 grams is added to another sample weighing 0.08753 grams. That is weight of sample 1 + weight of sample 2;
6.814 + 0.08753 = 6.90153grams
Next, the subsequent mixture is then divided into exactly 3 equal parts i.e. 6.90153grams divided by 3
= 6.90153/3
= 2.30051grams.
One of the equal parts is 2.30051grams, which is then multiplied by 7.6335 times I.e. 2.30051 × 7.6335 = 17.5609grams
Therefore, the final mass is 17.5609grams
