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sveta [45]
3 years ago
15

A spieces of extremely rare, deep water fish are slowly becoming extinct. If there are a total of 821 of this type of fish and t

here are 15% fewer fish each month, how many wil there be in half a year
Mathematics
1 answer:
Step2247 [10]3 years ago
6 0

Answer:

12 months in a year

6 is half a month so we're going off of 6 months.

So:

821*0.15= 123.15

821- 123.15= 697.85

697.85*0.15= 104.6775

697.85-104.6775= 593.1725

593.1725*0.15= 88.975875

593.1725-88.975875= 504.196625

504.196625 *0.15= 75.62949375

504.196625- 75.62949375= 428.56713125

428.56713125*0.15= 64.2850696875

428.56713125-64.2850696875 = 364.282061562

364.282061562*0.15= 54.6423092344

364.282061562-54.6423092344 = 309.639752328

So its 310 fish.

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9. If f(x) = 5x-4 and f(2a) =156 , then what is the value of a?
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