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Rina8888 [55]
3 years ago
15

Equation 1:Ax+By=C Equation 2:Dx+Ey=F A, B, C, D, E, and F are non-zero real numbers. Which of the following could replace equat

ion 1 and still have the same solution? Select all that apply. A.
A multiple of Equation 1.
B. The sum of Equation 1 and Equation 2
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2.
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2.
E. The sum of a multiple of Equation 1 and Equation 2.
Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D. 
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A scientist finds the temperature of a sample at the beginning of an experiment is t degrees celcius. After 1 hour, the temperat
ale4655 [162]
So the two possible original temperatures would be either -9 or 9.
6 0
3 years ago
Read 2 more answers
Multiply the following and write your answer In scientific notation.. 3.62 × 10^-5 · 9,400.
svet-max [94.6K]

Answer:

3.4028 x 10^-1

Step-by-step explanation:

First you make the 9400 into scientific notation:

9.4x10^3

Then you combine like terms

(3.62x9.4)(10^-5x10^3)

Finally you simplify

34.028x10^-2

3.4028x10^-1


6 0
3 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
3 years ago
4x square+ 8 x - 5=0<br><img src="https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20-%205%20%3D%200" id="TexFormula1
Damm [24]

Answer:

x = \frac{1}{2}

x = -\frac{5}{2}

Step-by-step explanation:

Solve Using the Quadratic Formula

     4x^2 + 8x − 5 = 0

Use the quadratic formula to find the solutions.

    −b ± √b^2 − 4 (ac)

     -------------------------

               2a

Substitute the values a = 4, b = 8, and c = −5 into the quadratic formula and solve for x.

    −8 ± √82 − 4 ⋅ (4 ⋅ −5)

     -------------------------

              2 ⋅ 4

Simplify the numerator.

Raise 8 to the p ower of 2.

     −8 ± √64 − 4 ⋅ 4 ⋅ −5

x=     ---------------------------

               2 ⋅ 4

Multiply −4 by 4.

        −8 ± √64 − 16 ⋅ −5

x =       -------------------------

                2 ⋅ 4

Multiply −16 by −5.

        −8 ± √64 + 80

x =       -------------------

               2 ⋅ 4

Add 64 and 80.

        −8 ± √144

x =        --------------

             2 ⋅ 4

Rewrite 144 as 12^2.

        −8 ± √122

x =       ------------

            2 ⋅ 4

Pull terms out from under the radical, assuming positive real numbers.

multiply 2 by 4          

        −8 ± 12

x=     ------------

            8

simplify

    −2 ± 3

x=   ---------

        2

The final answer is the combination of both solutions.

x= 1/2, -5/2

Hope this helped!

6 0
3 years ago
Read 2 more answers
(20 pts)
irakobra [83]

A function can be represented by equations and tables

  • 4 users are logged in by 9am
  • The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

g(x) = \frac14 \sqrt{x - 3} + 3

At 9am, x = 9.

So, we have:

g(x) = \frac14 \sqrt{9 - 3} + 3

g(x) = \frac14 \sqrt{6} + 3

Simplify

g(9) = 3.6

Approximate

g(9) = 4

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

x - 3 = 0

Solve for x

x = 3

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

g(x) = \frac14 \sqrt{x - 3} + 3

g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3

When x = 23, we have:

g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0
2 years ago
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