Answer:
Step-by-step explanation:
Hey, um, I dont know if ur still doing the whole stop the hackers thing, but there's this one user, echo2155, that I've seen post a link (or a bunch, not sure). I don't remember what they said, because their answer got deleted. I just figured I'd tell u, because I want to stop it too. It's really anoying when people do it on my questions becuz they use up a question and other people can't answer. I report as many as I can, but there's so many people that do it. I hope this is what ur looking for, bye!
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
Answer:
22
Step-by-step explanation:
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Answer:
19*7=133
Step-by-step explanation:
Hope you could get an idea from here.
Doubt clarification - use comment section.
