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3 years ago

Find the supplement of 80º (only answer with a number, not the word degrees)

Mathematics

1 answer:

Nana76 [90]3 years ago

8 0

Answer:

100°

Step-by-step explanation:

two angles are supplement .

if their sum is equal to 180°

supplement angle of 80° + x = 180°

180° - 80° = 100° answer

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If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

<u>Step-by-step explanation:</u>

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} } )$

⇒ $sin2\alpha = \frac{260}{\sqrt{269} }( \sqrt{\frac{1}{269} } )$

⇒ $sin2\alpha = \frac{260}{269}$

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3 years ago

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Alja [10]

Answer33

Step-by-step explanation:

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I believe it is x < 120 (Btw the < is supposed to have a line under but I can’t put one! Pls give brainliest if can)

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2 years ago

0.6630 divided by 0.51

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Step-by-step explanation:

1 act like the decimals aren't there then put 50:1 on the outside and 6630 on the inside and divide like normal

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Step-by-step explanation:

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