Answer:
C. y = 2x − 5
Step-by-step explanation:
Given equation of line
2x − y = 3
rewriting the equation in slope intercept form as answer are given slope intercept form
y = 2x - 3
slope intercept form of equation is
y = mx + c
where m is the slope
c is y intercept
thus
slope for y = 2x - 3 when comparing with y = mx + c is 2
now we know slope of two parallel line is same
thus,
the slope of line that is parallel to the line 2x − y = 3
is 2
Let the equation of required line be y = mx + c
where m = 2
thus
y = 2x + c is the new required equation
it passes through the point (2, −1)
using y = -1 and x = 2 in y = 2x + c
-1 = 2*2 + c
c = -1 - 4
c = -5
thus,
equation of required line is option c
y = 2x - 5 ----answer
Answer:
Donnys
Step-by-step explanation:
You get 10 bagels for $11 at Bobs, while you can get 12 bagels for less ($9).
I think that the answer would be 6+-8 because it equals -2 and 6-(-8)= -2
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
