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3 years ago

What is 2,069 is in the written

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

2.069x10^3

Step-by-step explanation:

Move the decimal places.

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Four ounces of a certain perfume cost 20$. How much would six ounces of perfume cost?

cupoosta [38]

Answer:

Step-by-step explanation:

you divide 20 by 4 then multiply that by 6

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3 years ago

What is the answer to 1.75g x 1000mg/1g?

Lerok [7]

1750mg in 1.75g just move the decimal place over three places. so its 1750mg

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3 years ago

Find the slope of the line containing the pair of points.<br> (6,5) and (0,0)

GarryVolchara [31]

Answer: 5/6

Step-by-step explanation:

Use slope formula of y2-y1/x2-x1. So here it doesn’t matter which is which so I did (6,5) x1 and y1 and (0,0) x2 and y2

So plugging it in it would be 0-5/0-6 = -5/-6 which simplifies to 5/6

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11 months ago

Which points are the vertices of the ellipse?

SIZIF [17.4K]

Answer

The points of intersection of the ellipse and its major axis are called its vertices. Here the vertices of the ellipse are A (a, 0) and A′ (− a, 0).

Step-by-step explanation:

4 0

1 year ago

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

4 0

2 years ago