Answer:
The speed in still water is 5 miles per hour.
Step-by-step explanation:
distance with current = 90 miles
distance against current = 10 miles
speed in still water = s
speed of current = 4 mph
speed with current = s + 4
speed against current = s - 4
time = t
speed = distance/time
distance = speed * time
With current:
90 = (s + 4) * t
Against the current:
10 = (s - 4) * t
We have a system of equations:
90 = (s + 4) * t
10 = (s - 4) * t
90 = ts + 4t
10 = ts - 4t
Subtract the second equation from the first equation.
80 = 8t
10 = t
t = 10
10 = t(s - 4)
10 = 10(s - 4)
1 = s - 4
s = 5
Answer: The speed in still water is 5 miles per hour.
Answer:
c. 12
Step-by-step explanation:
PA² = (BC + PB) × PB => tangent-secant theorem
PA = 8
PB = 4
BC = ?
Substitute
8² = (BC + 4) × 4
64 = 4BC + 16
64 - 16 = 4BC + 16 - 16
48 = 4BC
48/4 = 4BC/4
12 = BC
BC = 12
16 over 3 is the answer u write the numerator above the denominator 6 over 1 minus 2 over 3 6 times 3 over 1 x3 minus 2 over 3 u get 18 minus 2 over 3 and subtract 18 and 2 u get 16 over 3
By pythagorean theorem
a^2+b^2=c^2
We can find that PL is 12.65
and then by altitude theorem
MA*LA=PA^2
we can find the value of MA
12MA=16
MA=1.33
then by the pythagorean theorem
we can use to find PM
MA^2+PA^2=PM^2
so PM=4.22
then to find the are you multiply length by width
PM*PL
12.65*4.22
So the area is 53.38
0.77 is the answer to your question
