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MaRussiya [10]
3 years ago
5

An alloy of tin is 15% tin and weights 20 pounds. A second allow is 10% tin. How many pounds of the second alloy must be added t

o the first to get a 12% mixture?
30 lb

40 lb

60 lb
Mathematics
1 answer:
Fofino [41]3 years ago
8 0
Let x represent the amount to be added. The total amount of tin will be
  15%·20 + 10%·x = 12%·(20+x)
  (15%-12%)·20 = (12%-10%)·x
  3%·20/2% = x
  30 = x

30 pounds of 10% tin must be added to get a 12% mixture.
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Answer:

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Step-by-step explanation:

Given

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See attachment for base dimension

Required

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So, the area of CDEF is:

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<u>ABCG</u>

<u></u>AB= GC = 2<u></u>

<u></u>AG = BC = 2<u></u>

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So, the base area is:

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The volume is then calculated as:

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7 0
2 years ago
Which two terms in (3+14) +27 could you add to get a multiple of ten? ​
Aleksandr-060686 [28]

Answer:

3 and 27

Step-by-step explanation:

<u>Step 1:  Determine which two terms we can use</u>

We have the following numbers to choose from:  3, 14, 27

Adding two numbers to get a multiple of ten means that the number that we come up with needs to be divisible by ten.  For example:  20, 30, 50, 100 are all multiples of ten.

In this example the only one that would add up to create a multiple of ten is 27 and 3 which would give us 30 which is a multiple of 10.

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lianna [129]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Bingel [31]

Answer:

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Step-by-step explanation:

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