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stich3 [128]
3 years ago
14

Starchy grain is dominant over sugary corn. If, in a cross between these types, 58 of the progeny are sugary, how many of the pr

ogeny should be starchy
Biology
1 answer:
DaniilM [7]3 years ago
5 0

Let us solve first the phenotype of this problem.

Starchy grain = AA (dominant)

Sugary Corn = aa (recessive)

AA x aa = AaAa ; AaAa

<span>     A    A</span>

<span>a  Aa   Aa</span>

<span>a  Aa   Aa</span>

The result of the cross is that the progeny will become heterozygous.

<span>If there is 58 progeny sugary, there will also be 58 starchy. It is 50%.</span>

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