<span>In the past, human populations were controlled by </span>Disease and Famine
Answer:
I believe it's <em>size</em>
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
ans is c is correct pls mark me as brainlist pls
Answer: Non-living factors in an ecosystem.
2. A large region of land with a distinct climate and certain types of plant and animals.
Explanation:
. Biosphere
b. Biome
c. Population
d. Abiotc
e. Ecosystems
f. Biodiversity
g. Food Chain
h. Aquatic
i. Community
