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Ierofanga [76]
3 years ago
13

If the complex number x = 3 + bi and |x|2 = 13, which is a possible value of b?

Mathematics
1 answer:
Fed [463]3 years ago
8 0
X = 3 + bi

|x| = √(3² + b²)

|x| = √(9 + b²) ..............(a)

But from the question |x|² = 13

|x| = √13

Substitute this into equation (a)

|x| = √(9 + b²) ..............(a)

√13 = √(9 + b²) 

13 = 9 + b²

9 + b² = 13

b² = 13 - 9

b² = 4

b = √4

b = + or - 2

Possible value of b is +2   or - 2.

Cheers!
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siniylev [52]

Answer:

17852.5$

Step-by-step explanation:

I already answer this in another part, but here it is againa:

In this case, all you need to do is sum all the amounts and take out the down payment of 2500$

First, the car of 18,500 with the 6.5% sale tax, it would be:

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Then:

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6 0
3 years ago
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Mice21 [21]
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Hope this helps! :)
6 0
4 years ago
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5 0
3 years ago
25 points Please explain your answer, thank you!
Mashutka [201]

The answer is B.

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-3/x isn’t a polynomial term because the variable is in the denominator.

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