Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-4, -2), B(-2, -2), C(-2, 7)C(−2,7)C, D(-4, 7
What is the area of rectangle ABCD?

Answer 1

Answer:

The area of rectangle ABCD is $18\ units^2$

Step-by-step explanation:

Plot the figure to better understand the problem

we have the vertices

A(-4, -2), B(-2, -2), C(-2, 7), D(-4, 7)

see the  attached figure

The area of the rectangle is equal to

$A=LW$

where

L is the length

W is the width

In this problem we have

$L=BC=7-(-2)=9\ units$ ---> difference of the y-coordinates

$W=AB=-2-(-4)=2\ units$ ---> difference of the x-coordinates

substitute

$A=(9)(2)=18\ units^2$