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2 years ago

Which equation matches the given points? (0, 7.6), (1, 6.2), (2, 4.8), (3, 3.4), (4,2)

Mathematics

1 answer:

Cerrena [4.2K]2 years ago

4 0

The equation that matches the given points is g(x) = -1.4x + 7.6

The standard form of a linear equation is expressed as $g(x)=mx + b$

m is the slope of the line

b is the y-intercept:

Using the coordinate points (3, 3.4), (4,2)

$m=\frac{2-3.4}{4-3}\\m=\frac{-1.4}{1}\\m=-1.4$

Substitute m = -1.4 and the coordinate (4, 2) into the formula:

$2=4(-1.4)+b\\2=-5.6+b\\b=2+5.6\\b=7.6$

Get the required equation:

$g(x)=mx+b\\g(x)=-1.4x+7.6$

Hence the equation that matches the given points is g(x) = -1.4x + 7.6

Learn more on equation of a line here; brainly.com/question/9351428

You might be interested in

Triangle ABC is reflected across the line y=2x to map onto triangle RST. Select all statements that are true.

Anettt [7]

The reflection transformation in the question is a rigid transformation,

therefore, the image and the preimage are congruent.

The statements that are true are;

AB = RS

∠ABC ~ ∠RST

ΔABC = ΔRST

m∠BAC = m∠SRT

Reasons:

The given parameter are;

Triangle ΔABC is reflected across the line 2·X, to map onto triangle ΔRST

Required:

To select the true statements

Solution:

A reflection is a rigid transformation, therefore, the distance between corresponding points on the image and the preimage are equal.

Therefore;

AB = RS

BC = ST

AC = RT

Given that the image formed by a reflection is congruent to the preimage, we have;

ΔABC ≅ ΔRST

∠ABC ≅ ∠RST

m∠ABC = m∠RST by the definition of congruency

∠BCA ≅ ∠STR

m∠BCA = m∠STR by the definition of congruency

∠BAC ≅ ∠SRT

m∠BAC = m∠SRT by the definition of congruency

Therefore, the true statements are;

AB = RS; Image formed by rigid transformation

∠ABC ~ ∠RST; Definition of similarity

ΔABC = ΔRST; By definition of congruency

m∠BAC = m∠SRT; by the definition of congruency

Learn more here:

brainly.com/question/11787764

7 0

3 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$