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Kobotan [32]
3 years ago
13

Write the first five terms of the sequence in which the nth term is an = (n+3)!/n+3

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

the first five terms are

a1 = 6

a2 = 24

a3 = 60

a4 = 120

a5 = 210

Step-by-step explanation:

the experission used to find the five terms is

an = n3+ 3n2+ 2n

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2x^3-3x^2-11x+6 divide by x-3
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Answer: 2x^2+3x-2

Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

Your final step is to do \frac{-2x}{x} =-2. Write this -2 next to your other two parts

Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

2x^2+3x-2 times

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