Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
Answer:
The length of the shorter base of the little trapezoid trail is 1 mi.
Step-by-step explanation:
Let the shorter base of the large trapezoid is S and the larger base of the large trapezoid is L.
Similarly, assume that the shorter base of the small trapezoid is s and the larger base of the small trapezoid is l.
Since, the trapezoids are similar, so

Now, given that S = 2 mi, L = 8 mi and l = 4 mi and we have to find s.
So,
mi. (Answer)
Answer:

Step-by-step explanation:




Answer:c 20
Step-by-step explanation: