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VikaD [51]
4 years ago
12

how many ounces of pure water must be added to 50 ounces of a 15% saline solution to make a saline solution that is 10% salt

Mathematics
1 answer:
anygoal [31]4 years ago
7 0

50 ounces of 15% saline solution contains 0.15*50 = 7.5 ounces of salt.

Let x be the amount of pure water you add to this solution. Then you end up with (x + 50) ounces of this new solution. The amount of salt stays the same.

You want the new solution to have a concentration of 10%. This means you need

7.5 / (x + 50) = 0.1

==>  7.5 = 0.1(x + 50)

==>  7.5 = 0.1x + 5

==>  2.5 = 0.1x

==>  2.5/0.1 = 0.1x/0.1

==>  x = 25

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Step-by-step solution for: (√2+√10)^2
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5 0
3 years ago
The graph of y=f(x) is shown below. What are all of the read solutions of f(x) = 0?
Sveta_85 [38]

Answer:

0, -1, -3

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3 years ago
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3 years ago
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3 years ago
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