Question

According to this decay series chart, which is the proper order of nuclear particle emission that occurs during the transition from lead-214 to lLead-210?
A) Lead-214 changes to bismuth-214.
B) Bismuth-214 changes to polonium-214.
C) Polonium-214 changes to lead-210.

Answer 1

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is $^{4}_{2}\alpha$.

A beta particle is a particle with a negatively charged electron. Symbol of a beta particle is $^{0}_{-1}\beta$.

According to the given question, the decay series chart along with reaction equation are as follows.

(a)  Lead-214 changes to bismuth-214.

        $^{214}_{82}Pb \rightarrow ^{214}_{83}Bi + ^{0}_{-1}e$

(b)  Bismuth-214 changes to polonium-214.

        $^{214}_{83}Bi \rightarrow ^{214}_{84}Po + ^{0}_{-1}e$

(c)  Polonium-214 changes to lead-210.

         $^{214}_{84}Po \rightarrow ^{210}_{82} + ^{4}_{2}He$

Therefore, we can conclude that proper order of nuclear particle emission is beta, beta, alpha.