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KengaRu [80]
2 years ago
13

How many moles are in 1.204 x 10 to the 24th atoms of carbon

Chemistry
1 answer:
Mrrafil [7]2 years ago
3 0
Two moles because one moles would be 6.02×10 23 atoms 2 moles would equal twice that number of atoms
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Based on the information in the tables, what is the Enthalpy of the solution for each substance? Please help me with this proble
3241004551 [841]

Answer: mg(OH)2 = +37

Rbl = 31

RbOH= -83

mgl2= -144

Explanation: just did it on edge2020

5 0
2 years ago
Write the chemical formula of the following:
Elan Coil [88]

Answer:

1.Ca(OH)2

2.Mg(OH)2

3.Al2SO4

4.Na2CO3

5.Zn3(PO4)2

6.LiNO3

7.CuCO3

8. K2CO3

9.MgSO4

10.Ca3(PO4)2

5 0
3 years ago
In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo
NNADVOKAT [17]

Answer:

- 178 ºC

Explanation:

The  ideal gas law   states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁    (1)

and for the final conditions:

P₂V₂= n₂ R T₂    where   n₂ = n₁/2     then    P₂ V₂ = n₁/2 T₂    (2)

Assuming V₂ = V₁ and  dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂  / ( n₁ R T₁)      then  P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

T₂ = 95 - 273 = - 178 º C

6 0
3 years ago
A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
3 years ago
I made a cup of coffee on the stove and when I went to check on it four hours later, there was no more water in the kettle.
11Alexandr11 [23.1K]
No the water evaporated 
i think :) :) 

3 0
3 years ago
Read 2 more answers
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