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3 years ago

12

Please help im so confused???

2 answers:

Yuki888 [10]3 years ago

8 0

<span>5 * 7 = 35*8 =280 280/2 = 140 units answer is B</span>

Vadim26 [7]3 years ago

7 0

First, find the cross-section of the prism.

For this question, the 2D triangle is the cross-section of this prism, since it can be multiplied by a number to become the 3D prism in the question. To understand it better, imagine having triangular pieces of papers with the same dimensions, and stacking them all up. You will end up with a 3D prism.

What you have to do next, is identify the method to solve this problem:
Volume of prism
= Cross section × length of prism
= Area of triangle × 8
= 0.5 × (5 × 7) × 8
= 0.5 × (35) × 8
= 0.5 × 35 × 8
= 0.5 × 8 × 35
= 4 × 35
= 140 units^3 {Since the unit of the lengths of prism are not specified, use the word units instead. Also, since the value 140 is the volume of an object, remember to put the power of the unit to 3}

Hope this helps! :)

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Complete the statement. Round to the nearest hundredth if necessary.

mixas84 [53]

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3 years ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = e−4x, [0, 2] Yes, it does not m

Zigmanuir [339]

Answer:

(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.

(b) $c =0.51995$

Step-by-step explanation:

Given

$f(x) = e^{-4x};\ [0,2]$

Solving (a); Does the function satisfy M.V.T on the given interval

We have:

$f(x) = e^{-4x};\ [0,2]$

The above function is an exponential function, and it is differentiable and continuous everywhere

Solving (b): The value of c

To do this, we use:

$f'(c) = \frac{f(b) - f(a)}{b - a}$

In this case:

$[a,b] = [0,2]$

So, we have:

$f'(c) = \frac{f(2) - f(0)}{2 - 0}$

$f'(c) = \frac{f(2) - f(0)}{2}$

Calculate f(2) and f(0)

$f(x) = e^{-4x}$

So:

$f(2) = e^{-4*2} = e^{-8} = 0.00033546262$

$f(0) = e^{-4*0} = e^{0} = 1$

This gives:

$f'(c) = \frac{0.00033546262 - 1}{2}$

$f'(c) = \frac{-0.99966453738}{2}$

$f'(c) = -0.4998$

Note that:

$f'(x) = (e^{-4x})'$

$f'(x) = -4e^{-4x}$

This implies that:

$f'(c) = -4e^{-4c}$

So, we have:

$f'(c) = -0.4998$

$-4e^{-4c} =-0.4998$

Divide both sides by -4

$e^{-4c} =\frac{-0.4998}{-4}$

$e^{-4c} =0.12495$

Take natural logarithm of both sides

$\ln(e^{-4c}) =\ln(0.12495)$

$\ln(e^{-4c}) =-2.0798$

Apply law of natural logarithm

$\ln(e^{ax}) =ax$

So:

$-4c =-2.0798$

Solve for c

$c =\frac{-2.0798}{-4}$

$c =0.51995$

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yan [13]

Answer:

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Step-by-step explanation:

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