(GIVING BRAINLIEST) who can tell me what grade middle school starts in the U.S.A

A quadrilateral PQRS is inscribed in a circle, A quadrilateral PQRS is inscribed in a circle. The measure of angle PQR is 85 deg

sasho [114]

Answer:

Measure of arc PQR is 190°

Step-by-step explanation:

First have a sketch of the quadrilateral PQRS inside a circle

You should notice that the intercepted angle is ∠PSR

You should remember that the intercepted arc PQR is twice the intercepted angle ∠PSR

Find the intercepted angle ∠PSR

Remember that in a quadrilateral opposite angles add up to 180°

Hence;

∠PQR+∠PSR=180°

85 + ∠PSR=180°

∠PSR=180°-85°=95°

Find arc PQR

Arc PQR =2×∠PSR

Arc PQR=2×95°

=190°

3 0

3 years ago

The area of a circle, in terms of π, is 80π m2. Find the value of the radius. Give your answer as a simplified surd.

jolli1 [7]

Answer:

$r=4\sqrt{5}\:\: \sf m$

Step-by-step explanation:

$\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

Given:

Area = 80π m²

Substitute the given value into the formula and solve for r:

$\implies 80 \pi = \pi r^2$

$\implies \dfrac{80 \pi}{\pi} = \dfrac{\pi r^2}{\pi}$

$\implies 80=r^2$

$\implies \sqrt{r^2}=\sqrt{80}$

$\implies r=\sqrt{80}$

$\implies r=\sqrt{16 \cdot 5}$

$\implies r=\sqrt{16}\sqrt{5}$

$\implies r=\sqrt{4^2}\sqrt{5}$

$\implies r=4\sqrt{5}$

4 0

2 years ago

Read 2 more answers

Write first four terms of an AP when the first term is -2 and common difference is O.

Nina [5.8K]

<h3>Answer: -2, -2, -2, -2</h3>

Explanation:

If the common difference is 0, then we're adding 0 to each term to get the next term. However, adding 0 doesn't change the number. So that's why we have the same thing written four times.

As another example, let's say the common difference was 1 instead of 0. That would mean the first four terms are -2, -1, 0, 1 since we add 1 to each term to get the next one (eg: -2+1 = -1).

6 0

3 years ago

Read 2 more answers

What are the solutions of the equation?

Margaret [11]

Answer:

Option (C) is correct.

The solution of the quadratic equation $12x^2+11x-5=0$ is $x=\frac{1}{3}$ and $x=\frac{-5}{4}$