Answer:
(a) 0.119
(b) 0.1699
Solution:
As per the question:
Mean of the emission, 
million ponds/day
Standard deviation, 
million ponds/day
Now,
(a) The probability for the water pollution to be at least 15 million pounds/day:
= 1 - P(Z < 1.178)
Using the Z score table:
= 1 - 0.881 = 0.119
The required probability is 0.119
(b) The probability when the water pollution is in between 6.2 and 9.3 million pounds/day:
P(Z < - 0.86) - P(Z < - 1.96)
Now, using teh Z score table:
0.1949 - 0.025 = 0.1699
Answer:
9
Step-by-step explanation:
m = j^2 -7p
18 = j^2 -7(9)
18 = j^2 - 63
81 = j^2
√81 = √j^2
9 = j
Answer:
8.5$
Step-by-step explanation:
85 diveded by 10 is 8.5$.
Step-by-step explanation:
A factor is an independent variable that is manipulated in an experiment.
Every factor has two or more levels, which are different values of the factor.
A combination of factor levels is called a treatment.
There is one factor: number of jumps.
This factor has two levels: sets of 10 and sets of 20.
For a single factor experiment, the levels are also the treatments: Jump 10 program and Jump 20 program.
Answer:
1) 1/2
2) 1/13
3)1/169
Step-by-step explanation:
not sure about the last one
correct me if i am wrong
