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Rashid [163]
4 years ago
12

On April 15, 1999, a South Korean cargo plane crashed due to a confusion over units. The plane was to fly from Shanghai, China,

to Seoul, Korea. After takeoff plane climbed to 900 m. Then the first officer was instructed by the Shanghai tower to climb to 1500 m and maintain that altitude. The captain. after reaching 1450 m. twice asked the first officer at what altitude they should fly. He was twice told incorrectly they were to be at 1500 ft. The captain pushed the control column quickly forward and started a steep descent. The plane could not recover from the dive and crashed. How much above the correct altitude did the captain think they were when he started his rapid descent and lost control? (It turns out that aircraft altitudes are given in feet throughout the world except in Chine, Mongolia, and the former Soviet states where meters are used.)
Physics
1 answer:
sattari [20]4 years ago
6 0

Answer:

993 m or 3257 ft

Explanation:

The captain was told to fly at at 1500 ft altitude. At the rate of 3.28 ft to 1 m, this is

\dfrac{1500}{3.28}=457 metres.

Since he was at 1450 m, he thought he was above the correct altitude by

1450 - 457 = 993 m.

In feet, this is

993 * 3.28 = 3257 ft

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Answer:

140 J

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By substitution,

K.E =  \frac{1}{2} \times 70 \times  {2}^{2}

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\implies K.E =140

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3 years ago
During normal beating, the heart creates a maximum 4.00-mV potential across 0.300 m of a person’s chest, creating a 1.00-Hz elec
erik [133]

Answer:

(a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is 4.433\times10^{-11}\ T

(c). The wavelength of the electromagnetic wave is 3\times10^{8}\ m

Explanation:

Given that,

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Distance = 0.300\ m

Frequency = 1.00 Hz

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Using formula of the potential difference

\Delta V=Ed

E=\dfrac{\Delta V}{d}

E=\dfrac{4.00\times10^{-3}}{0.300}

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(b). We need to calculate the maximum magnetic field strength in the electromagnetic wave

Using formula of the maximum magnetic field strength in the electromagnetic wave

B=\dfrac{E}{c}

Put the value into the formula

B=\dfrac{0.0133}{3\times10^{8}}

B=4.433\times10^{-11}\ T

(c). We need to calculate the wavelength of the electromagnetic wave

Using formula of wavelength

c=f\lambda

\lambda=\dfrac{c}{f}

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{1.00}

\lambda=3\times10^{8}\ m

Hence, (a). The maximum electric field strength is 0.0133 V/m.

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3 years ago
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Answer:

1. a_{rad}=17545.2\frac{m}{s^{2}}

2. a=4429.45 \frac{m}{s^{2}}

Explanation:

Radial acceleration is:

a_{rad}=\frac{v^2}{r} (1)

With r the radius respects the axis of rotation and v the tangential velocity that is related with angular velocity (ω) by:

v= \omega r (2)

By (2) on (1):

a_{rad}= \frac{(\omega r)^2}{r}= (\omega )^2r=(418,88\frac{rad}{s})^2(0.1m)

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To find the acceleration of the tube with the fall, we can use the expression:

\overrightarrow{J}=\overrightarrow{F}_{avg}(\varDelta t) (3)

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\overrightarrow{p}_{f}-\overrightarrow{p}_{i}=\overrightarrow{F}_{avg}(\varDelta t)

And using Newton's second law (F=ma) and that (P=mv):

mv_f-mv_i=(ma)(\varDelta t) (5)

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\frac{mv_i}{2}=mgh

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-m(4.43)=(ma)(\varDelta t)

solving for a:

a=\frac{4.43}{\varDelta t}=\frac{4.43}{1.0\times10^{-3}}=-4429.45

It’s negative because is opposed to the tube movement.

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