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2 years ago

Hello people ~

Physics

2 answers:

ASHA 777 [7]2 years ago

5 0

The charge would be in equilibrium so there would be no charge in the body of the conductor.

Answer:

(b) there cannot be any charge in the body of the conductor

Mamont248 [21]2 years ago

3 0

Answer:

Explanation:

Note the line that there is no charges anywhere else outside means the charge is placed in equilibrium position.

Hence there cannot be any charge in the body of conductor

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PLS HELP ILL GIVE U A BRAINLEST

Ipatiy [6.2K]

Answer:

The car on the left side picture was on the left side it moved to right in the picture on the right

Explanation:

the car moved from left to right

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3 years ago

The logarithm of x, written log(x), tells you the power to which you would raise 10 to get x. So, if y=log(x), then x=10^y. It i

Lelechka [254]

Answer:

Explanation:

The function which is inverse to exponentiation is called logarithm.

It is of the form

$log\ x=y\\\Rightarrow log_{10}\ x=y\\\Rightarrow 10^y=x$

The 10 here is the base of the logarithm. The logarithm with base 10 is called common logarithm

$log_{10}1000000=y\\\Rightarrow 10^y=1000000\\\Rightarrow 10^6=1000000\\\Rightarrow y=6$

So, log(1,000,000) = 6

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4 years ago

What is the kinetic energy of a 1 kg pie if it is thrown at 10 m/s?

nignag [31]

Given

mass (m) = 1 kg

velocity (v) = 10 m/s

kinetic energy ( ke) = ?

,we know

K.E =1/2 m v²

= 1/2 * 1 * 10²

= 100/2

=50 joule

hope it helps :)

7 0

3 years ago

Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp

Gekata [30.6K]

The length of rod in terms v(r) and t is L = [ Δt / (1/343) - (1/v(r)) ].

3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.

At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.

The time interval is given by t = L/v.

The delay between pulses arrivals is:

Δt = L [(1/v(air)) - (1/v(copper))]

Now,

When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).

The speed of air, v(air) = 343 m/s

Then,

L = [ Δt / (1/v(air)) - (1/v(r)) ]

L = [ Δt / (1/343) - (1/v(r)) ]

Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.

Learn more about speed here:

brainly.com/question/13943409

#SPJ4

8 0

1 year ago

If you hold your arm outstretched with palm upward, the force to keep your arm from falling comes from your deltoid muscle. assu

Maurinko [17]

Your question seems to be incorrect. Please check below:

What force must the deltoid muscle provide to keep the arm in this position? By what factor does this force exceed the weight of the arm?If you hold your arm outstretched with palm upward, as in (Figure 1) , the force to keep your arm from falling comes from your deltoid muscle. Assume that the arm has mass 4 kg and the distances and angles shown in (Figure 1) .

F=?
F/w= ?

The answer is 339 N

4 0

3 years ago