Question

A 70.0-kilogram man is walking at a speed if 2.0 m/s. What is the kinetic energy?

Answer 1

Answer:

140 J

Explanation:

From the the question, the mass of the man =70.0 kg and the speed at which the man is walking =2.0 m/s.

$K.E = \frac{1}{2}m {v}^{2}$

where K.E = the kinetic energy, m=mass and v= speed.

By substitution,

$K.E = \frac{1}{2} \times 70 \times {2}^{2}$

$\implies \: K.E = \frac{280}{2}$

$\implies K.E =140$

Hence the kinetic energy of the man is 140J