What is the complete factorization of the polynomial below?<br> 8 + 5x²-x-5

Determine whether the given linear equations are parallel, perpendicular, or neither.

ladessa [460]

Answer:

A. Perpendicular

Step-by-step explanation:

Lines are perpendicular if their slopes are opposite reciprocals of each other. Opposite, meaning if positive, the other slope is negative, and if negative, the other slope is positive. Reciprocal meaning, the number is flipped upside down, turning fractions into whole numbers and vice versa.

1/9

-1/9

-9

The slopes are perpendicular

4 0

2 years ago

Which answer choice is a solution to the inequality 1.5x + 3.75 greater than or equal to 5.5

irga5000 [103]

Answer:

x≥ $\frac{7}{6}$

Step-by-step explanation:

given 1.5x+3.75≥5.5

→ 1.5x≥5.5-3.75

→ 1.5x≥1.75

→ x≥ $\frac{1.75}{1.5}$

→ x≥ $\frac{7}{6}$

8 0

3 years ago

Read 2 more answers

the function 56-4y=-5x can be used to determine the total amount of money in a coin jar,y,after money is added for x days. what

notka56 [123]

Answer:

23

Step-by-step explanation:

4 0

2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago

The price of a gallon of unleaded gas has dropped to $2.83 today. Yesterday's price was$2.89 . Find the percentage decrease. Rou

alexandr1967 [171]

Decrease = initial price - final price

% decrease = [ (initial price - final price) / initial price ] *100

% decrease =[ (2.89 - 2.83) / 2.89] * 100 = 2.08, which can be rounded to 2.1

Answer: 2.1 %

5 0

3 years ago

Read 2 more answers

What is the complete factorization of the polynomial below? 8 + 5x²-x-5