Answer:
A. 228.5
B. 10
Step-by-step explanation:
A. Since <em>x</em> represents the number of months, replace <em>x</em> with 6 in the equation. Then multiply 29x6, which equals 174. Then add 174+54.5, which equals 228.5.
B. You need to solve for <em>x</em> by switching the signs in the equation<em>. </em>Set the original equation (29x+54.5) equal to 344.50. To solve for <em>x, </em>first subtract 344.50-54.5, which equals 290 (you subtract because it's the opposite of adding). Then divide 290÷29, which equals 10. You can check your work by replacing <em>x</em> in the original equation with 10, and if you get 344.5, your answer is correct.
Good luck :)
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
14:16 21:24 28:32 are three ratios that are equivalent
Answer:
6) 102
7) 58
NOTE: Supplementary add to 180° and Complementary add to 90°
<u><em>Please mark as brainliest if answer is right </em></u>
Have a great day, be safe and healthy
Thank u
XD
f(x) cannot be 0 or less than zero, but can approach+ infinity
Answer is (0, ∞)
