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boyakko [2]
3 years ago
12

How do you solve this equation

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
8 0

Remember the order of operations: Parentheses, Exponents, Multiplication/Division, Addition/Subtraction

Solve the expressions in parentheses first.

There is an expression within parentheses that is also in an expression within brackets. Solve that expression first:

6 - 10 = -4

The expression in brackets will now read:

[4 - 3(-4)]

Multiply 3(-4):

3 \cdot -4 = -12

[4 - (-12)]

Solve the expression:

4 - (-12) = 4 + 12 = 16

The problem should now look like this:

(8-2)^2 + \frac{1}{4}(16)

Solve the expression in parentheses that has an exponent:

8 - 2 = 6

(6)^2 = 6 \cdot 6 = 36

Solve the term with 1/4 as a coefficient:

\frac{1}{4}(16) = 4

The expression should now look like this:

36 + 4 =  \boxed{40}

The answer is 40.

tankabanditka [31]3 years ago
7 0

(8 - 2)² + 1/4[4 - 3(6 - 10)]

Solve this expression using PEMDAS. (M/D and A/S are not in order, they are solved from left to right)

  1. Parentheses
  2. Exponents
  3. Multiplication
  4. Division
  5. Addition
  6. Subtraction

According to PEMDAS, we are going to solve inside the parentheses (brackets) first.

Solve (6 - 10) inside the brackets first.

  • (8 - 2)² + 1/4[4 - 3(-4)]

Solve the multiplication inside the brackets (-3 * -4).

  • (8 - 2)² + 1/4[4 + 12]

Add 4 + 12 inside the brackets.

  • (8 - 2)² + 1/4[16]

Now solve (8 - 2) to complete the P step in PEMDAS.

  • (6)² + 1/4(16)

Next step in PEMDAS is E, exponents. Solve (6)².

  • 36 + 1/4(16)

Next step in PEMDAS is M, multiplication, so multiply 1/4(16).

  • 36 + 4

The last step is to add 36 and 4 together.

  • 36 + 4 = 40
<h3>Your answer is <u>40.</u></h3>
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Step-by-step explanation:

The line touches the y-intercept at 3 and then goes down 3 units (-3) and then right 2 units.

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In a study of the effect of cooling rate on the hardness of welded joints, 50 welds cooled at a rate of 10°C/s had an average Ro
Studentka2010 [4]

Answer:

a) The 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

b) No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =91.1 represent the sample mean 1

\bar X_2 =90.7 represent the sample mean 2

n1=50 represent the sample 1 size  

n2=40 represent the sample 2 size  

s_1 =6.55 sample standard deviation for sample 1

s_2 =4.32 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Part a

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =91.1-90.7=0.4

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=50+40-2=88  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,88)".And we see that t_{\alpha/2}=1.987  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=1.325

Now we have everything in order to replace into formula (1):  

0.4-1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=-1.887  

0.4+1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=2.687  

So on this case the 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

Part b

No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

3 0
3 years ago
What is the value S in the equation 3r= 10+5s, when r=10?
MrRa [10]
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Read 2 more answers
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Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

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De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

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