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4 years ago

Answer please need answers

Mathematics

2 answers:

jasenka [17]4 years ago

5 0

answer deleted:

Reason

Not so fast...Your answer does not provide any work or examples as to why it is right. Always show your work and include any information that may be helpful to your peers. This is the only way they'll be able to learn how to tackle the problem on their own in the future. Thanks! http://brainly.ninja/us/us-community-guidelines

I Write again:

<h2>Being polite and using good manners when in the cyber comunity</h2><h2></h2>

(This answer teach something to moderators)

Step2247 [10]4 years ago

5 0

Answer:

being polite and using good manners when in the cyber community

Step-by-step explanation:

search it up!

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Use the table to determine the location with the greatest amount of rainfall and the location with the least amount of rainfall.

Kryger [21]

Step-by-step explanation:

I think it is hilo hawii 480 cm it has the longest cm

7 0

3 years ago

What is the simplified form of the following expression?

geniusboy [140]

Answer:

242

Step-by-step explanation:

Simplify the following:

11 ((9^2 - 5^2)/2^2 + 8)

Hint: | Evaluate 2^2.

2^2 = 4:

11 ((9^2 - 5^2)/4 + 8)

Hint: | Evaluate 5^2.

5^2 = 25:

11 ((9^2 - 25)/4 + 8)

Hint: | Evaluate 9^2.

9^2 = 81:

11 ((81 - 25)/4 + 8)

Hint: | Subtract 25 from 81.

| 7 | 11

| 8 | 1

- | 2 | 5

| 5 | 6:

11 (56/4 + 8)

Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.

The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:

11 (14 + 8)

Hint: | Evaluate 14 + 8 using long addition.

| 1 |

| 1 | 4

+ | | 8

| 2 | 2:

11×22

Hint: | Multiply 11 and 22 together.

| 2 | 2

× | 1 | 1

| 2 | 2

2 | 2 | 0

2 | 4 | 2:

Answer: 242

3 0

3 years ago

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) = speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

$23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)$

simplifying the equation, we get

$23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)$

$23(2.8+2.8)/29=2.8^2-x^2$

$x^2=(2.8)^2-(23*5.6)/29)=3.4$

$x=\sqrt{3.4}=1.84m/s$

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

4 0

2 years ago

Find the nearest number before and after any real number.

Mkey [24]

Answer:

add 1 and subtract 1

Step-by-step explanation:

so if u add and subtract 1. take 5. 5+1 and -1 is 4 and 6

Hope this helps :D

6 0

4 years ago

A rectangular box which is open at the top can be made from an12-by-18-inch piece of metal by cutting a square from each corner

algol [13]

Answer:

h=2.35in, l=13.3in and w=7.3in

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram that will represent the prolem. (Look at attached picture)

From the diagram we can see that the length ad the width of the box are found by using the following expressions:

L=18-2x

W= 12-2x

H=x

next, we can make use of the volume formula of a rectangular prism, which is the following:

V=WLH

so we can substitute the expressions we got before on the formula:

V=x(12-2x)(18-2x)

and for ease of calculation, we can multiply the terms, so we get:

$V=x(216-24x-36x+4x^{2})$

$V=x(4x^{2}-60x+216)$

$V=4x^{3}-60x^{2}+216x$

So now we can find the derivative of the volume:

$V'=12x^{2}-120x+216$

and set it equal to zero, so we get:

$12x^{2}-120x+216=0$

and now we can solve. We can start by factoring the left side of the equation, so we get:

$12(x^{2}-10x+18)=0$

which yields:

x^{2}-10x+18=0

This one can only be solved by using the quadratic formula:

$x=\frac{-b\pm \sqrt{-b^{2}-4ac}}{2a}$

so we substitute the corresponding values:

$x=\frac{-(-10)\pm \sqrt{-(-10)^{2}-4(1)(18)}}{2(1)}$

which yields:

x=7.65in or x=2.35in

we keep the 2.35in only, because the 7.65in returns an impossible box, since that would make the width a negative width.

So the 2.35in height would give us the greatest box. Now we can use it to find the height, the width and the length of the box.

Height=x=2.35

W=12-2x=12-2*2.35=7.3in

L=18-2x=18-2(2.35)=13.3in

5 0

3 years ago