The perimeter of a rectangle is 84 cm. if the length is 25 cm, how wide is the rectangle?

1 answer:

6 0

P = 2(L + W)
P = 84
L = 25
now sub

84 = 2(25 + W)
84 = 50 + 2W
84 - 50 = 2W
34 = 2W
34/2 = W
17 = W <=== the width is 17 cm

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3 years ago

How do you work this out

Digiron [165]

Check the picture below.

notice, is just a circle inscribed in a square.

now for the first one, we know the diameter is 14, so the square is a 14x14, and the radius of that is half the diameter or 7.

now, if we get the area of the square, which includes the area of the circle, and THEN get the area of the circle and subtract it from the square's, what's leftover is the shaded section.

$\bf \textit{area of a circle}\\\\ A=\pi r^2\\\\
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now, for the one on the right-hand-side, the radius is 8, and square's area is 16x16,

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4 years ago

Emma is making a scale drawing of her farm using the scale 1cm = 2.5ft. In the drawing she drew a well with a diameter of 0.5 ce

Y_Kistochka [10]

Scale : 1 cm = 2.5 ft

1 cm = 2.5 ft
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4 years ago

How to solve this? Is the question correct? ty :)

bezimeni [28]

Answer:

The proposition is true.

Step-by-step explanation:

Now we proceed to demostrate that expression given is true by algebraic means:

1) $\frac{x^{-1}+y^{-1}}{x^{-1}}+\frac{x^{-1}-y^{-1} }{y^{-1}}$ Given

2) $\frac{y^{-1}\cdot (x^{-1}+y^{-1})+x^{-1}\cdot (x^{-1}-y^{-1})}{x^{-1}\cdot y^{-1}}$ $\frac{a}{b} + \frac{c}{d} = \frac{a\cdot d+b\cdot c}{b\cdot d}$

3) $\frac{x^{-1}\cdot y^{-1}+y^{-2}+x^{-2}-x^{-1}\cdot y^{-1}}{x^{-1}\cdot y^{-1}}$ Distributive property/ $a^{b}\cdot a^{c} = a^{b+c}$

4) $\frac{x^{-2}+y^{-2}}{(x\cdot y)^{-1}}$ Commutative, associative and modulative properties/Existence of additive inverse/ $a^{b}\cdot c^{b} = (a\cdot c)^{b}$

5) $[(x\cdot y)^{-1}]^{-1}\cdot (x^{-2}+y^{-2})$ Commutative property/Definition of division

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