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3 years ago

A set of 4 consecutive integers adds up to 202. What is the greatest of these integers?

Mathematics

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

Step-by-step explanation:

When asked such a question, try to use trial and error.

For example, the total is 202 and is made of of 4 integers which are consecutive(follow each other)

If you were to divide 202 by 4, you would get approximately 50

So, it would be best to try and add certain consecutive numbers(making sure 50 is one of them) till you get a total of 202

In this case, the integers would be, 49, 50, 51 and 52

The question then further asks you ti find out which is the greatest of these integers. That would be 52

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10. There are 355 students at Median Middle School. If there 8% of the students were absent on Tuesday, how many students were a

Setler79 [48]

To solve this question, we simply need to divide the total amount of students by 8% to find out how many students were absent and how many were present.

However, we can't simply multiply it by 8%, so we need to turn that into a decimal.

8% - 0.08

Multiply:

355 x 0.08

= 28.4

Round:

28 kids were absent

Subtract:

355 - 28

= 327

This means that 28 kids were absent, and 327 kids were present.

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1 year ago

Please help Find f(-3). f(x) = 4x + 7 A) -5 B) 5 C) 6 D) 10

irina1246 [14]

Answer:

Step-by-step explanation:

To evaluate f(- 3) substitute x = - 3 into f(x), that is

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3 years ago

2n+7+7n=13+3n+8n please help

Rasek [7]

first combine like terms so 2n + 7n which is 9n

so 9n + 7 = 13 + 3n + 8n

then combine on other side so 9n + 7 = 13 + 11n

then subtract 7 to 13 so 6

sp 9n + 6 = 11n

then subtract 9 to the other side so 2n

6 = 2n then divide all by 2

n= 3

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3 years ago

Which relation represents a function?

Tom [10]

C is the rigth answer because all the other three has two x values in common. :)

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3 years ago