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Maurinko [17]
3 years ago
10

A set of 4 consecutive integers adds up to 202. What is the greatest of these integers?

Mathematics
1 answer:
lbvjy [14]3 years ago
7 0

Answer:

52

Step-by-step explanation:

When asked such a question, try to use trial and error.

For example, the total is 202 and is made of of 4 integers which are <u>consecutive</u>(follow each other)

If you were to divide 202 by 4, you would get approximately 50

So, it would be best to try and add certain consecutive numbers(making sure 50 is one of them) till you get a total of 202

In this case, the integers would be, <em>49, 50, 51</em> and <em>52</em>

The question then further asks you ti find out which is the greatest of these integers. That would be <em>52</em>

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Calculate the area of quadrilateral ABCD.<br> State the units of your answer.
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Answer:

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Step-by-step explanation:

Quadrilateral ABCD is composed of 2 right triangles

Construct the line BD, then

Δ ABD and Δ BCD are the 2 right triangles.

The area (A) of a triangle is calculated using

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Δ ABD with b = 18 and h = 7.5

A = \frac{1}{2} × 18 × 7.5 = 9 × 7.5 = 67.5 cm²

Δ BCD with b = 15.6 and h = 11.7

A = \frac{1}{2} × 15.6 × 11.7 = 7.8 × 11.7 = 91.26 cm²

Thus

area of ABCD = 67.5 + 91.26 = 158.76 cm²

3 0
3 years ago
Here’s the answer you need to know
vovikov84 [41]
Thank you sooo much Maddi441
8 0
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Plz help I will give brainliest
natali 33 [55]

Answer:

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5 0
2 years ago
Find f(x) =32<br> f(x)=3x-1
SIZIF [17.4K]

Answer:

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Step-by-step explanation:

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