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3 years ago

A set of 4 consecutive integers adds up to 202. What is the greatest of these integers?

Mathematics

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

Step-by-step explanation:

When asked such a question, try to use trial and error.

For example, the total is 202 and is made of of 4 integers which are consecutive(follow each other)

If you were to divide 202 by 4, you would get approximately 50

So, it would be best to try and add certain consecutive numbers(making sure 50 is one of them) till you get a total of 202

In this case, the integers would be, 49, 50, 51 and 52

The question then further asks you ti find out which is the greatest of these integers. That would be 52

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Factoring with Algebra Tiles Represent the quadratic polynomial 2x2 + x – 6 using algebra tiles and determine the equivalent fac

Nezavi [6.7K]

Answer:

Two zero pair

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Step-by-step explanation:

We are given the following quadratic equation:

$f(x) = 2x^2+x-6$

Since, this a quadratic equation we would have two zero pairs for this model.

Factored form of polynomial:

$f(x) = 2x^2+x-6\\f(x)=2x^2+ 4x -3x -6\\f(x)=2x(x+2)-3(x+2)\\f(x)=(2x-3)(x+2)$

is the required factored form of the given polynomial.

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2 years ago

Read 2 more answers

Please someone explain the question and explain the answers probably

Taya2010 [7]

Okay so all you are doing is filling out the char to do this you fine the increasing rate or the pattern. so 2*3=6 5*3=15 so the pattern is that you are multiplying every input by 3 so 0*3=0
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