All categories

3 years ago

Is the given sequence arithmetic? If so, identify the common difference. 3.2, 3.5, 3.8, 4.1, . . .

Mathematics

2 answers:

mojhsa [17]3 years ago

8 0

Yes the common difference is .3

sweet [91]3 years ago

3 0

3.5 - 3.2 = 3.8 - 3.5 = 4.1 - 3.8 = 0.3 (common difference)

You might be interested in

IS THIS RIGHT OH NO

OverLord2011 [107]

Answer:

the top are right im not sure about bottom

7 0

2 years ago

Marquis is hungry for pizza! He has a choice between pizza A: Half of a 16 inch pizza or pizza B: A whole 10 inch pizza to himse

aliina [53]

Answer:

The 10 inch one because half of 16 is 8 so he would only get 8 inches of pizza.

Step-by-step explanation:

5 0

3 years ago

Find the derivative of g(y)=(y-4)*(2y+y^2)

sasho [114]

Answer:

$g'(y)=3y^2-4y-8$

Step-by-step explanation:

start by foiling out the given function

$g(y)=(y-4)(2y+y^2)\\=2y^2+y^3-8y-4y^2\\=y^3-2y^2-8y$

next, use the power rule to find the derivative

power rule: To use the power rule, multiply the variable's exponent n, by its coefficient a, then subtract 1 from the exponent. If there's no coefficient (the coefficient is 1), then the exponent will become the new coefficient.

$g'(y)=3y^2-4y-8$

5 0

1 year ago

Ok find the value of two numbers if their sum is 70 and their difference is 36 what the answer

cluponka [151]

58 and 22 is the answer.

8 0

3 years ago

Plz help with equation of the circle will award fastest CORRECT answer with brainliest

aliina [53]

Answer:

$(x-1)^2+(y-2)^2=6.25$

Step-by-step explanation:

The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let (1,2) be x₁ and y₁ and let (2.5,4) be x₂ and y₂. Therefore:

$d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5$

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25$

3 0

3 years ago