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3 years ago

In ΔABC, the measure of ∠C=90°, the measure of ∠A=64°, and AB = 2.7 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics

2 answers:

harina [27]3 years ago

3 0

Answer:

Applying sine theorem for right triangle ABC, we have:

sin A = BC/AB

=> BC = AB x sin A = 2.7 x sin(64 deg) = ~2.4 (ft)

Hope this helps!

Vlada [557]3 years ago

3 0

BC=AB x sinA=2.7 x sin64'=2.4

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Answer:

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2 years ago

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In a scale drawing, a building has a length of 15 cm. The actual length of the building is 37.5 feet. Whats the scale of the dra

Feliz [49]

Answer:

$\frac{15}{37.5}\ \frac{cm}{ft}$

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we know that

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$\frac{15}{37.5}\ \frac{cm}{ft}$

That means

15 cm in the drawing represent 37.5 ft in the actual

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divide by 30.48

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2 years ago

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2 years ago

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